Horizontal tank calculator

The volume and area of the surface of a fluid in a horizontal cylinder

The surface to volume ratio of a fluid within the horizontal tank


Surface to volume | Convert 20 US gallon to weight for: compounds | foods | gravels

The volume of fluid
in the horizontal tank
= 20

Imperial gallon16.65oil barrel0.48
liter75.71US gallon20

The surface to volume ratio of fluid in the horizontal tank
= 0.45

Surface area to volume ratio is also known as surface to volume ratio and denoted as sa÷vol, where sa is the surface area and vol is the volume.

Angle, α

degree70.53radian1.23
Unit
The surface area of fluid
in the horizontal tank
Aside
= 132		Atop
= 791.96		Abottom
= 1 034.01		Atotal
= 2 089.97
centi­meter²851.635 109.416 670.9913 483.66
foot²0.925.57.1814.51
inch²132791.961 034.012 089.97
meter²0.090.510.671.35
Unit
The
depth
of
fluid
= 8		The
length
of
arc
of
fluid
= 29.54
centi­meter20.3275.04
foot0.672.46
inch829.54
meter0.20.75
Unit
The length, radius
and diameter of the
horizontal tank
Length
= 35		Radius
= 12		Dia­meter
= 24
centi­meter88.930.4860.96
foot2.9212
inch351224
meter0.890.30.61
 
  • About this page:  Horizontal tank calculator
    • How to find the amount of fluid in a horizontal tank of a cylindrical shape?
      V = Aside×L = [r² ×(π ⁄ 2−arcsin(1−h ⁄ r))−(r−h)×√h×(2×r−h)]×L
    • How to find the area of the side surface of fluid in a horizontal tank?
      Note, this side of fluid comes in contact with the circular base of the horizontal cylindrical tank.
      Aside = r² ×(π ⁄ 2−arcsin(1−h ⁄ r))−(r−h)×√h×(2×r−h)
    • How to find the area of the top surface of fluid in a horizontal tank?
      Atop = 2×L×√r²−(r−h)²
    • How to find the area of the bottom surface of fluid in a horizontal tank?
      Abottom = larc×L
    • How to find the area of the total surface of fluid in a horizontal tank?
      Atotal = 2×Aside+Atop+Abottom
    • What is the valid range of values for the depth of fluid?
      0 ≤ h ≤ 2×r
    • How to find the angle that draws a half of the side arc of fluid within a horizontal tank?
      • α = π−arccos((h−r) ⁄ r),  where h > r;
      • α = arccos((r−h) ⁄ r),  where 0 ≤ h ≤r.
    • How to find the length of arc created by rotating radius r from the left‐most to the right‐most point of fluid within a horizontal tank?
      larc = 2×r×α
      • larc = 2×r×(π−arccos((h−r) ⁄ r)),  where h > r;
      • larc = 2×r×arccos((r−h) ⁄ r),  where 0 ≤ h ≤r.
    • How to find the diameter of a horizontal tank?
      d = r×2
    • How to find the radius of a horizontal tank?
      r = d ⁄ 2
    • where:
      • α  is the angle created by 2 radial lines. The first radial line intercects the top surface of fluid, and the second radial line coincides with the line of the depth of fluid h. This is the angle that draws a half of the side arc with length ½larc);
      • larc  is the length of the arc of the side surface of a fluid, where the fluid comes in contact with the circular base of the horizontal cylindrical tank.
    • The value of π.

      The pi (π) is approximately equal to 3.14159265359 and represents the ratio of any circle's circumference to its diameter, or the ratio of a circle's area to the square of its radius in Euclidean space.

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